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Alexus [3.1K]
3 years ago
7

HELP PLEASE! DUE TMR! Answer whichever ones you want and i can try to deal with the rest. I just have alot of work and need extr

a help
1) what are the roots of p(x)=64 - x^3


2)What are the solutions of x^3 (x^2 + 8x - 20)


3) find the zeros to the polynomial x^3 - 3x^2 - 10x


4) create an equation with the following roots: -4 , 4 , -3 , 2/5 (fraction)


5) create an equation with the following roots: ± 2i , -7 , 1


6) find all the zeros on the following polynomial: 2x^3 - 11x^2 - 16x + 105

Given zero: 5
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answers

1) 4

2) 0, 2, -10

3) 0, 5, -2

Step-by-step explanation:

1) x³ - 64 = 0

x³ = 64

x = 4

2) x³(x² + 8x - 20) = 0

x³(x² + 10x - 2x - 20) = 0

x³(x(x + 10) - 2(x + 10)) = 0

x³(x + 10)(x - 2) = 0

x = 0, 2, -10

3) x³ - 3x² - 10x = 0

x(x² - 3x - 10) = 0

x(x² - 5x + 2x - 10) = 0

x(x(x - 5) + 2(x - 5)) = 0

x(x - 5)(x + 2) = 0

x = 0, 5, -2

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30a^6-24a^2\\ GCF\; is \; 6a^2\\ \\ 30a^6-24a^2=6a^2(\frac{3a^6}{6a^2} -\frac{24a^2}{6a^2} )=6a^2(5a^4-4)\\ ---------------------\\ \\ 16a^5-20a^3\\ GCF \; is \; 4a^3\\ \\ 16a^5-20a^3=4a^3(\frac{16a^5}{4a^3} -\frac{20a^3}{4a^3})=4a^3(4a^2-5) \\ ---------------------\\ \\ 12a^3+8a\\ GCF \; is \; 4a\\ \\ 12a^3+8a=4a(\frac{12a^3}{4a}+\frac{8a}{4a})=4a(3a^2+2)\\   ---------------------\\ 24a^4+18\\GCF \; is \; 6\\\\24a^4+18=6(\frac{24a^4}{6} +\frac{18}{6})=6(4a^4+3) \\    ---------------------

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