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2 years ago

If m< DBG=58 and mDG =74 , find mGE

Mathematics

1 answer:

mestny [16]2 years ago

5 0

Answer:

Option D: mGE = 190°

Step-by-step explanation:

From the property of angles of secant and tangent lines, we have:

DBG = (mGE - mDG)/2

(That is, the angle in point B is half the difference of the larger arc by the smaller arc defined by the lines)

So, we have that:

58 = (mGE - 74)/2

2*58 = mGE - 74

mGE = 116 + 74 = 190°

So we have that mGE is equal to 190°, correct option: D.

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Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.

Alexxandr [17]

Answer:

So total number which is not divisible by 11 = 89999-8181 = 81819

Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

$T_N=a+(n-1)d$ , here a is first term, d is common difference and n is number of terms

So $99990=10010+(n-1)11$

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

4 0

2 years ago

If f(x) = 2x2 + 2 and g(x) = x2 - 1, find (f - g)(x)I

erastovalidia [21]

9514 1404 393

Answer:

C. x^2 + 3

Step-by-step explanation:

Substitute for f(x) and g(x) and simplify.

(f -g)(x) = f(x) -g(x)

(f -g)(x) = (2x^2 +2) -(x^2 -1) = 2x^2 +2 -x^2 +1

(f -g)(x) = x^2 +3

4 0

2 years ago

One wet weekend, 0.86 inches of rain fell on saturday. the next day, 1.52 inches of rain fell. how many inches of rain fell over

nataly862011 [7]

0.86 + 1.52 = 2.38 inches of rain fell over the weekend

4 0

3 years ago

Read 2 more answers

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud

SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

$M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }$

The 85% confidence level $z_{\alpha } = 1.44$

$\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}$

$\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}$

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

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2 years ago

If 3/4 is the dividend and -2/5 is the divisor then what is the quotient ?

Alexxx [7]

Answer:

$\dfrac{-15}{8}$