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Vladimir79 [104]
3 years ago
15

A teacher writes the following product on the board:

Mathematics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

Zhenghao is correct

Step-by-step explanation:

We have that:

(2x+3)(x + 4) = x² + 7x + 12

The only two factors of  x² + 7x + 12 different from 1 ,-1 and and itself are (2x+3) and (x + 4)

If Hafsana says that (x + 3) is a factor of x² + 7 + 12, He or she is not correct.

If Zhenghao says that x² + 7x + 12 is divisible by 2x + 3, He or she is correct because (2x + 3) is a factor of x² + 7x + 12

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Answer:

\frac{1}{2}  =  {2}^{ - 1}

Step-by-step explanation:

remember the property

{a}^{ - n}  =  \frac{1}{ {a}^{n} }

then u get equation with same base

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4 years ago
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Someone please help me with 6 and 7 and please show work
kap26 [50]
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4 years ago
How to determine the amount of zeroes of a function?
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4 years ago
Question 5: prove that it’s =0
mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that \cos(\frac{2}{x}) is a variable number between -1 and 1 (inclusive).

This means that -1 \le \cos(\frac{2}{x}) \le 1.

x^4 \ge 0 for all value x. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

By squeeze theorem, if  -x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

and \lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L, then we can also conclude that \im_{x \rightarrow} x^4\cos(\frac{2}{x})=L.

So we can actually evaluate the "if" limits pretty easily since both are continuous  and exist at x=0.

\lim_{x \rightarrow 0}x^4=0^4=0

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We can finally conclude that \lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0 by squeeze theorem.

Some people call this sandwich theorem.

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3 years ago
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