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3 years ago

8

Are these two questions correct?

2 answers:

jok3333 [9.3K]3 years ago

6 0

Yes! You answered them correctly!!

Oksanka [162]3 years ago

3 0

Answer:

Yes you answered them both correctly.

Step-by-step explanation:

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Which is 9.5 expressed as a fraction in simplist form

stealth61 [152]

Answer:

9 1/2

Step-by-step explanation:

9 and a half

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3 years ago

Read 2 more answers

Help ! I AM Not sure what to do

o-na [289]

The answer is (3,5)

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2 years ago

PLEASE HELP ASAP I DON'T UNDERSTAND

Ira Lisetskai [31]

The slope of a linear equation will tell you the price of each ticket. The y-intercept tells you the convenience fee.
We can find the slope by choosing two points and finding the slope.
m = (y2 - y1)/(x2 - x1)
m = (887.40 - 231.15)/(20 - 5)
m = 656.25/15
m = 43.75
Each ticket will cost $43.75

4 0

3 years ago

Markus is finding that it takes too long to track down all of the groceries he needs to buy from a given store. GroceryGrabbr to

swat32

Answer:

A. The grocery list the user input

Step-by-step explanation:

4 0

3 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago