3 years ago

F. If you add § + ģ + , the sum is g. If you add 3 + 2, what is the sum?

Mathematics

1 answer:

inna [77]3 years ago

5 0

Answer:

g. 3+2 =5

..........................

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andrezito [222]

Answer:

$\frac{(a+b)}{a^{2} -b^{2} }$ + $\frac{(a-b)}{a^{2} -b^{2} }$ = $\frac{2a}{a^{2} -b^{2} }$

Step-by-step explanation:

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3 years ago

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Mina compro un queso que pesaba 3/4 de kilo .si lo partió en 1/8 de kilo cada una ¿cuantas porciones de queso pudo sacar ?

Ksju [112]

Answer:

Tenemos.

Lo que compro de queso = 3/4 k

Cada pedazo pesa = 1/8k

Número de pedazos = (3/4)/(1/8)

Número de pedazos = (3 *8)/(4*1) = 24/4 = 6

Respuesta.

Salen 6 pedazos

Step-by-step explanation:

5 0

3 years ago

Mary's backpack weighs 6 pounds. How many kilograms does Mary's backpack weigh? Round your answer to the nearest hundredth. (1 k

ratelena [41]

6 lbs x 1 kg/2.2 lbs = 6/2.2 kg = 2.727272 kg ≈ 2.72 kg

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3 years ago

A sample of 20 account balances of a credit company showed an average balance of $1,170 and a standard deviation of $125. You wa

Lady_Fox [76]

Answer:

The P-value for this test is P=0.2415.

Step-by-step explanation:

We have to perform an hypothesis testing on the mean of alla account balances.

The claim is that the mean of all account balances is significantly greater than $1,150.

Then, the null and alternative hypothesis are:

$H_0: \mu=1150\\\\H_a: \mu>1150$

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.

We can calculate the t-statistic as:

$t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{1170-1150}{125/\sqrt{20}}=\dfrac{20}{27.95}=0.7156$

The degrees of freedom fot this test are:

$df=n-1=20-1=19$

For this one-tailed test and 19 degrees of freedom, the P-value is:

$P-value=P(t>0.7156)=0.2415$

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4 years ago

Easy 50 points, one multi choice question

kotegsom [21]

D is the correct answer

6 0

3 years ago

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