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3 years ago

Two points located on jk are j (-1,-9) and k (5,3). What is the slope of jk?

Mathematics

2 answers:

Ivenika [448]3 years ago

7 0

Answer:

Step-by-step explanation:

slope of line= $\frac{y1 - y2}{x1 - x2}$

slope of JK

$= \frac{3 - ( - 9)}{5 - ( - 1)} \\ = \frac{3 + 9}{5 + 1} \\ = \frac{12}{6} \\ = 2$

Natalka [10]3 years ago

7 0

Answer:

Slope = 2

Step-by-step explanation:

Slope = $\frac{rise}{run}$

Slope = $\frac{3+9}{5+1}$

Slope = $\frac{12}{6}$

Slope = 2

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3 years ago

Solve for x.<br><br> 2(4x− 9) = 5(x − 4)

cluponka [151]

Answer:

2(4x− 9) = 5(x − 4)

=>8x- 18= 5x-20

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3 years ago

Which is the zero of the function f(x)=(x+3) (2x-1)(x+2) ?

Scrat [10]

Answer:

x= -3 x = 1/2 x=-2

Step-by-step explanation:

f(x)=(x+3) (2x-1)(x+2)

Set equal to zero

0 =(x+3) (2x-1)(x+2)

Using the zero product property

x+3 =0 2x-1 =0 x+2 =0

x= -3 2x =1 x = -2

x= -3 x = 1/2 x=-2

6 0

3 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0

2 years ago