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Elan Coil [88]
3 years ago
6

Two points located on jk are j (-1,-9) and k (5,3). What is the slope of jk?

Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

2

Step-by-step explanation:

slope of line= \frac{y1 - y2}{x1 - x2}

slope of JK

=  \frac{3 - ( - 9)}{5 - ( - 1)}  \\  =  \frac{3 + 9}{5 + 1}  \\  =  \frac{12}{6}  \\  = 2

Natalka [10]3 years ago
7 0

Answer:

Slope = 2

Step-by-step explanation:

Slope = \frac{rise}{run}

Slope = \frac{3+9}{5+1}

Slope = \frac{12}{6}

Slope = 2

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<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

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<h3>b) 0.4 \div  ( - 0.75)</h3><h3>■Convert the decimals into a fractions</h3>

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<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, Quotient is -  \frac{8}{15}</h3>

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<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, The Quotient is -  \frac{8}{15}</h3>
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