Question

Two points located on jk are j (-1,-9) and k (5,3). What is the slope of jk?

Answer 1

Answer:

2

Step-by-step explanation:

slope of line= $\frac{y1 - y2}{x1 - x2}$

slope of JK

$= \frac{3 - ( - 9)}{5 - ( - 1)} \\ = \frac{3 + 9}{5 + 1} \\ = \frac{12}{6} \\ = 2$

Answer 2

Answer:

Slope = 2

Step-by-step explanation:

Slope = $\frac{rise}{run}$

Slope = $\frac{3+9}{5+1}$

Slope = $\frac{12}{6}$

Slope = 2