I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Answer:
99 cents
Step-by-step explanation:
one quarter=25 cents
nine pennies= 9 cents
six dimes= 60 cents
one nickle= 5 cents
25+9+60+5=85+14=99
Answer: d
Step-by-step explanation: because every x has 1 y
Answer:
-46
Step-by-step explanation:
2×2=4-50 lol lol lol
Answer:
Question 1: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question 2: Options 1, 2, 5
Step-by-step explanation:
Question #3
Step 1: Factor
2x^5 − 54x^2
2x^2(x^3 - 27)
<em>2x^2(x - 3)(x^2 + 3x + 9)</em>
<em />
Answer: Option C, 2x^2(x - 3)(x^2 + 3x + 9)
Question #2
p(x) = 4x^6 + 32x^3
<u>Step 1: Factor</u>
4x^6 + 32x^3
4x^3(x^3 + 8)
<em>4x^3(x + 2)(x^2 - 2x + 4)</em>
<em />
Answer: Options 1, 2, 5