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Paraphin [41]
3 years ago
8

WILL MARK BRAINLIEST PLEASE HELP

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:  

2x + (-2x + 3) = 3

2x - 2x +3

0 + 3

3

2x-7 + (-2x) = -7

2x -2x - 7

0 -7

-7

-(5x -1) + 5x = 1

-5x +1 + 5x

-5x + 5x + 1

0 + 1

1

Step-by-step explanation: In addition, the parentheses help identify the individual addends. If adding a negative number, it is the same as subtracting. If there is a negative sign outside the parentheses, as in example c, you must distribute it: the signs of the numbers within the parentheses must be reversed when the parentheses are removed.

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Mr. Robert is a real estate agent, he earns 5% commission of his total sales. If he sold a property for $135,000. How much commi
mel-nik [20]

Answer:

ok if I did this right the answer should be 675. sorry if it's wrong. I hope it's right.

5 0
2 years ago
How do you find the slope of a line on a graph?
Fynjy0 [20]

Answer:

the slope of a line is the rise over run from plot to plot.

a. 3/5

b. 3/4

c. 2

Step-by-step explanation:

i hope this helps :)

6 0
2 years ago
Read 2 more answers
A retailer sells a refrigerator for a list price of $1,200. The retailers cost was $850. What is the percentage of the markup?
matrenka [14]

Answer:

41%

Step-by-step explanation:

1200-850=350

350 is the markup, now we need the percentage

the orginal price was 850 so we just need to divide 350 by 850

we get 0.4117...

convert that to a percentage and we have 41% markup

8 0
3 years ago
The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h
DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

<em>Let X = lifetime of a battery in a certain application</em>

So, X ~ N(\mu=16,\sigma^{2} =2^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean lifetime = 16 hours

            \sigma = standard deviation = 2 hours

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

  P(X > 19) = P( \frac{  X -\mu}{\sigma} > \frac{19-16}{2} ) = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                              = 1 - 0.9332 = 0.0668

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.</em>

Hence, the probability that a battery will last more than 19 hours is 0.0668.

5 0
3 years ago
Help plz someone help me plz ty
MrRa [10]

Answer: 18.75 for each girl

Step-by-step explanation:

First you take the unit rate 2.50 multiply by 5.

2.50 x 5 = 12.50

12.50 x 3 = 37.50

37.50 / 2 = 18.75

7 0
3 years ago
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