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3 years ago

If the price of a purse increased from $45 to $54, what was the percent of increase

Mathematics

2 answers:

Marrrta [24]3 years ago

5 0

If you set it up in cross multiplication then you would have (x/100 = 45/54) then cross multiply so then i would look like this (54x/4,500) so from there you would divide 54 from 4,500 i hope this helps in any way oh and it should come up to be 83.3333333 which would be 83% lol

Dimas [21]3 years ago

4 0

There is a 20% increase.

Work is provided in the image attached.

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You have 14 coins that are nickles and quarters that equals 2 dollars how do you solve using substitution?

sergejj [24]

Answer:

The question is incorrect but if half nickels and quarters exist then you could say the answer is 7.5 nickels and 6.5 quarters.

The problem:

14 coins that are either nickels are quarters

The total dollar amount of these coins is 2 dollars

Step-by-step explanation:

Let n be the number of nickels.

Let q be the number of quarters.

We are given that n+q=14 and that .05n+.25q=2.

I'm going to choose to solve the system by elimination.

Multiplying the first equation by .25 gives:

.25n+.25q=.25(14)

.25n+.25q=3.5

So let's line the equations up now:

.25n+.25q=3.5

.05n+.25q=2

---------------------If we subtract the equations, the variable q will be eliminated. Thus, we will able to solve for the variable n.

.20n+0q=1.5

.20n=1.5

Dividing both sides by .2 gives:

n=7.5

If n=7.5 and n+q=14, then we have 7.5+q=14 by substitution property.

We can subtract 7.5 on both sides giving us:

q=14-7.5=6.5

We cannot have 7.5 nickels and 6.5 quarters but this satisfies the given information.

Check:

7.5+6.5=(7+6)+(.5+.5)=13+1=14

7.5(.05)+6.5(.25)=2

Now, the requested way which is by substitution:

Let n be the number of nickels.

Let q be the number of quarters.

We are given that n+q=14 and that .05n+.25q=2.

We can solve the first equation for either n or q and then substitute that into the other equation allowing us to solve for the other variable.

Let's solve for q by subtraction n on both sides:

q=14-n

We are going to replace q in the second equation with (14-n) giving us:

.05n+.25(14-n)=2

Distribute:

.05n+3.5-.25n=2

Combine like terms:

-0.2n+3.5=2

Subtract 3.5 on both sides:

-0.2n=-1.5

Divide both sides by -0.2:

n=7.5

Since q=14-n and n=7.5, then q=14-7.5=6.5 .

We are already check the solution above.

8 0

2 years ago

Solve for x. x - 8 = -10

Tresset [83]

Answer: -2

Step-by-step explanation: add the -8 to both sides to get X by itself

-10 + 8 = -2

7 0

2 years ago

Find the height of a rectangular prism if the surface are is 288 square centimetres and the base has a length of 4 centimetres a

liraira [26]

The rectangular prism below is made up of 6 rectangular faces, and the faces opposite to each other are have an equal area.
The area of one of the faces is lxh or lh, and the area of the face opposite to it is also equal, so the area of those two equal faces is 2lh.
The area of the base of the prism is lxw, and the area of its opposite face is equal, so the area of those two equal faces is 2lw.
The area of the face in the left side of the prism is wxh, and the area of the face opposite to it is also equal, so their combined area is 2wh.
So, to find the total surface area of a rectangular prism, we’d add the sum of all the rectangular faces, so the formula of finding the surface area of a rectangular prism=
2lh+2lw+2wh
=2(lh+lw+wh)
Given,
Surface area of the rectangular prism=288 cm^2
2(lh+lw+wh)=288
2[4h+(4x9)+9h)]=288
4h+(4x9)+9h=288/2
4h+(4x9)+9h=144
13h+36=144
13h=144-36
13h=108
h=108/13
h=8.308 cm
Hope this helps!