Answer:
a) Upwards
b) x = -1
c) (-1,-9)
d) x intercepts; (2,0) and (-4,0)
y intercept is (0,-8)
Step-by-step explanation:
a) As we can see, the parabola faces upwards
b) To find the axis of symmetry equation, we look at the plot of the graph and see the point through the vertex of the parabola that exactly divides the parabola into two equal parts
The x-value that the line passes through here is the point x = -1 and that is the equation of the axis of symmetry
c) The vertex represents the lowest point of the circle here,
As we can see, this is the point through which the axis of symmetry passes through to make a symmetrical division of the parabola
We have the coordinates of this point as
(-1,-9)
d) The intercepts
The x-intercept are the two points in which the parabola crosses the x-axis
We have this point as 2 and -4
The x-intercepts are at the points (2,0) and (-4,0)
For the y-intercept; it is the y-coordinate of the point at which the parabola crosses the y-axis and this is the point (0,-8)
Answer:
thank me
Step-by-step explanation:
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
The answer is 7 because it goes 10th 100th and the thirty one is thousands
Step-by-step explanation:
take the base square. find the diagonal
16^2+16^2 = 2*16^2= d^2
d= 16√2
half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10
