Answer:
x = 13
y = -10
z = -7
Step-by-step explanation:
x+y+z=−4
2x+3y−2z=10
−x+2y−3z=−12
Add the first and the third equations to eliminate x
x+y+z=−4
−x+2y−3z=−12
--------------------
3y -2z = -16 Equation A
Add the second and twice the third equation to eliminate x
2x+3y−2z=10
−2x+4y−6z=−24
----------------------------
7y -8z = -14 Equation B
Take Equation A and multiply by -4
-4*( 3y -2z) = (-16)*-4
-12y + 8z = 64
Add this to Equation B
-12y + 8z = 64
7y -8z = -14
-----------------------
-5y = 50
Divide by -5
-5y/-5 = 50/-5
y = -10
Now using equation A
3y -2z = -16
3*-10 -2z = -16
-30 -2z = -16
Add 30 to each side
-2z = -16+30
-2z = 14
Divide by -2
-2z/-2 = 14/-2
z = -7
Now find x using the first equation
x+y+z = -4
x -7-10 = -4
x -17 = -4
Add 17 to each side
x-17+17 = -4+17
x = 13
uh i'm not sure i think its 2,also im having a terrible day so thank you :3
We know that
[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube
The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=<span>5 cm
T</span>he biggest block was 729 cm³------> b3=√729------> b3=<span>9 cm
[</span><span>the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm
</span><span>
the answer is
</span>the stack of blocks was 18 cm tall<span>
</span>
60! 3.4(60)=204 so the answer is 60
Answer:
<em>In 5 years the product of their ages will be 208</em>
Step-by-step explanation:
The age of two children is 11 and 8 years.
Let's call x the number of years ahead.
We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:
(11+x)(8+x)=208
Operating:
Simplifying:
Factoring:
(x-5)(x+24)=0
Solving:
x=5, x=-24
The negative solution is not valid, thus x=5
In 5 years the product of their ages will be 208