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3 years ago

Solve for u . -24 = u ÷ 6 u = ?

Mathematics

2 answers:

laila [671]3 years ago

7 0

-24=u/6
multiply by 6 both sides
-24*6=-144
-144=u

Ainat [17]3 years ago

5 0

-24=u/6 just times 6 to both sides -24*6=-144 rewrite
-144=u
Hope this helps have a nice day

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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

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3 years ago

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ella [17]

From my work I believe it should be the third one.

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3 years ago

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Georgia [21]

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3 years ago

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iragen [17]

Answer:

<h3> $\boxed{ \bold{ \sf{ \huge{ \boxed{ a = - 36}}}}}$ </h3>

Step-by-step explanation:

$\sf{ \frac{a}{9} = - 4}$

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Multiply the numbers

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Hope I helped!

Best regards!!

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3 years ago

Complete the coordinate proof of the theorem. Given: A B C D is a rectangle. Prove: The diagonals of A B C D are congruent.

Inessa05 [86]

Step-by-step explanation:

<u>Given coordinates of the rectangle ABCD:</u>

A(0, 0), B(a, 0), C(x, y), D(0, b)

Lets first find coordinates of C

We can see that A and B are on same line horizontally, so C and D will be on the parallel line

The distance AB and CD are equal also distance AD and BC are equal, therefore

AB = a - 0 = a, CD = a
AD = b - 0 = b, BC = b

<u>So the coordinates of C are:</u>

x = a, y = b

<u>Now the diagonals:</u>

AC = √(a-0)² + (b-0)² = √a²+b²
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Since AC = BD, we can state they are congruent

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3 years ago

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