Question

A 620 kg car is traveling at 24 m/s on horizontal ground when it starts up a 30 m high hill. The engine can produce up to 144,000 J of work during that time. What is the kinetic energy of the car at the top of the hill?

Answer 1

Answer:

The kinetic energy of the car at the top of the hill is 140280 Joules.

Explanation:

Mass of the car, m = 620 kg

Speed of the car, v = 24 m/s

Height of the hill, h = 30 m

The engine can produce up to 144,000 J of work during that time, W = 144,000 J

We need to find the kinetic energy of the car at the top of the hill. It can be calculated using conservation of mechanical energy as :

$(mgh+K)-\dfrac{1}{2}mv^2=144000$

$(620\times 9.8\times 30+K)-\dfrac{1}{2}\times 620\times (24)^2=144000$

$620\times9.8\times30+K=322560$

$K=140280\ J$

So, the kinetic energy of the car at the top of the hill is 140280 Joules. Hence, this is the required solution.