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Natalka [10]
2 years ago
8

Imagine a negative test charge sitting at the coordinate origin (0,0). Two bunches of positive charges are located on the x-axis

and the y-axis, respectively, so that the vectors of the respective electric forces, which the test charge experiences, point from the origin at points (1,0) and (0,1), respectively. The total force vector, which the test charge experiences, points from the origin at the point __________
Physics
1 answer:
Oxana [17]2 years ago
5 0

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

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Which of the following statements are true at some time during the course of the motion? Check all that apply. Check all that ap
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Answer:

The object can have zero velocity and, simultaneously, nonzero acceleration.

The object can have zero acceleration and, simultaneously, nonzero velocity.

The object can have nonzero velocity and nonzero acceleration simultaneously.

Explanation:

An object in simple harmonic motion has a total mechanical energy (sum of elastic potential energy and kinetic energy) that is constant:

E=U+K=1/2kx^2 + 1/2}mv^2

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m is the mass

v is the speed

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F=-kx

In Newton's law F = ma, this can be also be written as

ma=-kx

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From the first equation, we can now states that:

When the displacement is zero, x=0, the acceleration is zero, a=0, and the velocity is maximum

When the velocity is zero, v=0, the acceleration is maximum, which occurs when the displacement is maximum

In all the other intermediate situations, both velocity and acceleration are nonzero.

So the correct answers are

The object can have zero acceleration and, simultaneously, nonzero velocity.

The object can have nonzero velocity and nonzero acceleration simultaneously.

The object can have zero velocity and, simultaneously, nonzero acceleration.

4 0
3 years ago
Read 2 more answers
A projectile is launched vertically at 100 m/s. If air resistance can be ignored, at what speed will it return to its initial le
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<h2>Speed with which it return to its initial level is 100 m/s</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 100 m/s  

Acceleration, a = -9.81 m/s²  

Final velocity, v = ?

Displacement, s = 0 m  

Substituting  

v² = u² + 2as

v² = 100² + 2 x -9.81 x 0

v² = 100²

v = ±100 m/s

+100 m/s is initial velocity and -100 m/s is final velocity.

Speed with which it return to its initial level is 100 m/s

7 0
2 years ago
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Hello!

\large\boxed{p = 5  \text{ } kgm/s}

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Plug in the given mass and velocity into the equation:

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