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Airida [17]
3 years ago
5

What times what times what equals 66

Mathematics
2 answers:
maks197457 [2]3 years ago
6 0

You have several choices ... 16 of them I think:

<span>1 x 66 .
2 x 33 .
3 x 22 .
6 x 11 .

-- Each of the same ones, with both numbers negative.

-- Each of the same ones, with the numbers in the opposite direction

-- Each of the same ones, with the numbers negative
   AND in the opposite direction.</span>

Rufina [12.5K]3 years ago
3 0
The answer is 11 x 6=66
That 11, 6, and 1 are some of the factors of 66. 
So we use 11 and 6 and we get 66. 
This is only the easiest factors we can multiply. 
There are many more factors that you can multiply together and get 66. 

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
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Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

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