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3 years ago

What times what times what equals 66

2 answers:

maks197457 [2]3 years ago

6 0

You have several choices ... 16 of them I think:

<span>1 x 66 .
2 x 33 .
3 x 22 .
6 x 11 .

-- Each of the same ones, with both numbers negative.

-- Each of the same ones, with the numbers in the opposite direction

-- Each of the same ones, with the numbers negative
AND in the opposite direction.</span>

Rufina [12.5K]3 years ago

3 0

The answer is 11 x 6=66
That 11, 6, and 1 are some of the factors of 66.
So we use 11 and 6 and we get 66.
This is only the easiest factors we can multiply.
There are many more factors that you can multiply together and get 66.

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NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

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Answer:

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Step-by-step explanation:

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