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HACTEHA [7]
3 years ago
8

Convert the angle 45°29'13" to decimal degrees and round to the nearest hundredth of a degree

Mathematics
2 answers:
KIM [24]3 years ago
5 0

Answer:

The answer is 45.49\°

Step-by-step explanation:

we know that

1\ degree =60\ minutes

1\ degree =3,600\ seconds

In this problem we have

45\°29'13''        

Convert to decimal degrees          

45\°29'13''=45\°+\frac{29}{60}\°+ \frac{13}{3,600}\°=45.49\°

Bad White [126]3 years ago
4 0
Add this. 45+ \frac{29}{60}+ \frac{13}{3600}
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A part time seamstress made $8881.93 last year. If she claimed herself as an exemption for $3650 and had a $5700 standard deduct
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Answer:

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Step-by-step explanation:

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3 years ago
What is y-4=3(x+3)<br><img src="https://tex.z-dn.net/?f=y%20-%204%20%3D%203%28x%20%2B%203%29" id="TexFormula1" title="y - 4 = 3(
aleksandr82 [10.1K]

Answer:

y-4=3(x+3)

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6 0
3 years ago
Each block in Ton’s neighborhood is 2/3 mile long if he walk 4 1/2 blocks how far does he walk?
nataly862011 [7]

if each block is 2/3 miles long, and he walks 4 1/2 blocks, we can simply multiply to two. It looks like this:

(2/3)(4 1/2)

to multiply, make 4 1/2 into an improper fraction and multiply normally

(2/3)(9/4)

Ton walks 3 miles total.

3 0
3 years ago
Line m is parallel to line p. m ∠ HEF = 39º and m ∠ IGF = 13º. Find the m ∠ EFG. Explain in detail how you know you are correct.
svetlana [45]

Answer:

The measure of ∠EFG is 52°

Step-by-step explanation:

Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.

In ΔJFG,

By angle sum property of triangle, which states that sum of all angles of triangle is 180°

m∠FJG+m∠JGF+m∠JFG=180°

⇒ 39°+13°+m∠JFG=180°

⇒ m∠JFG=180°-39°-13°=128°

As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair

⇒ m∠JFG+m∠EFG=180°

⇒ 128°+m∠EFG=180°

⇒ m∠EFG=52°

The measure of ∠EFG is 52°

6 0
3 years ago
Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x
alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0
3 years ago
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