9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
1.) The error is that she attached the
variable with the flat fee (which is
constant) and put the daily rent as a
constant (which is variable).
The correct equation is:
365+125x=250+175x
2.) N=5
3.) k=-35.
Explanation: Solution:
17k-6=37k+4 . 17k-37k=4+6 .
-27k=10 . k=10\cdot(7-2) . k=-35 .
4.)

.
Answer:
free points cuz this was five days ago!! LETS GOOOOOO
Step-by-step explanation:
Answer:
y = -2x + 4
Step-by-step explanation:
y = mx + b
m ---> slope
b ----> y-intercept
y = -2x + 4
The plus sign inside the parenthesis indicates that the shift is to the left, And the formula for the period is 2pi/B and our B is 4, so 2pi/4 = pi/2 which is 90. So your answer is the third one down, left 60 period 90