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Ad libitum [116K]

3 years ago

11

Which factorization is incorrect?

1 answer:

mote1985 [20]3 years ago

3 0

The answer is 3)
Just sub any number you want into the equation and calculate it.
For example of 3）
When m=1
Left hand size=1+3-4+12=12
Right hand size=-1x4=-4
Left hand size≠Right hand size
It is incorrect.

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When dividing Fractions do you criss cross like when you multiply?

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> $\alpha = 0.05$ There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u> is <u>different from</u> <u>at least of the population</u>

Step-by-step explanation:

From the question we are told that the claim is

The mean growth rates of all four species are equal.

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Th alternative hypothesis is

$H_a: at \ least \ one \ of \ the \ means \ is \not\ equal$

From question the p-value is $p-value = 0.015$

And since the $p-value < \alpha$ so the null hypothesis will be rejected

So

The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> $\alpha = 0.05$ There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u> is <u>different from</u> <u>at least of the population</u>

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Answer:

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Step-by-step explanation:

We are given that a quadratic equation

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$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

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And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

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