Ask question

Ask question

All categories

3 years ago

9

How do I solve this 1-2

2 answers:

zepelin [54]3 years ago

6 0

Answer:

1. 1.

2. 62.

Use PEMDAS.

ch4aika [34]3 years ago

5 0

Use photo math. it helps.

You might be interested in

The perimeter of the shape is ______<br><br> feet.

Vika [28.1K]

Answer:

Step-by-step explanation:

1. add the side lengths

$10+4+4+2+2+4+4+6\\= 36 ft$

4 0

3 years ago

Read 2 more answers

In what base is the sum of 8 and 5 equal to 14?

LuckyWell [14K]

Nothing. It would have to be 5 and 8 to be 13... Not 14 and it would be math. :)

4 0

3 years ago

At a particular music store, CDs are on sale at $13.00 for the first one purchased and $10.00 for each additional disc purchased

netineya [11]

D=Disc
13+10d=83
10d=83-13
10d=70
D=70/10
D=7
7+1=8
Maria purchased 8 CDs. Hope this helps!

7 0

3 years ago

Read 2 more answers

Solve the quadratic equation -x^2=4

Alex_Xolod [135]

<span>-x^2=4
x = -2i and x = 2i
-------------------------------</span>

7 0

3 years ago

Read 2 more answers

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

so

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

<u>case B)</u> point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

<u>case C)</u> point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

<u>case D)</u> point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

<u>case E)</u> point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

<u>case F)</u> point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

<u>the answer is</u>

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

3 years ago

Read 2 more answers