<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
chan eil agad ach sgrùdadh a dhèanamh air google!
5x-50 = 30-15x, 20x = 80, x = 4,
x=4!
Answer:
![xy^\frac{2}{9} = x*\sqrt[9]{y^2}](https://tex.z-dn.net/?f=xy%5E%5Cfrac%7B2%7D%7B9%7D%20%3D%20x%2A%5Csqrt%5B9%5D%7By%5E2%7D)
Step-by-step explanation:
Given

Required
The equivalent expression (see attachment)
We have:

Split

Apply the following laws of indices
![y^\frac{m}{n} = \sqrt[n]{y^m}](https://tex.z-dn.net/?f=y%5E%5Cfrac%7Bm%7D%7Bn%7D%20%3D%20%5Csqrt%5Bn%5D%7By%5Em%7D)
So, we have:
![xy^\frac{2}{9} = x*\sqrt[9]{y^2}](https://tex.z-dn.net/?f=xy%5E%5Cfrac%7B2%7D%7B9%7D%20%3D%20x%2A%5Csqrt%5B9%5D%7By%5E2%7D)
<em>Hence (d) is correct</em>
Answer:
Look just at finding the linear model. Two points. Use price per gallon for x and gallons per hour sold for y. Your two points (x,y) are (2.15,1600) and (2.55,800).
Slope m=%281600-800%29%2F%280.15-0.55%29
m=800%2F0.40
m=2000
Using point-slope form for a line, and the lower-y point,
y-800=2000%28x-2.55%29
highlight%28y=2000%28x-2.55%29%2B800%29