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creativ13 [48]
3 years ago
8

Work out 8 x(3 + 7)​

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0

Answer:

Answer is 80

Step-by-step explanation:

PEMDAS (Parentheses - Exponents - Multiplication - Division - Addition - Subtraction)

Do (3+7) first which equals 10.

Your equation is then simply 8 x 10 which is 80.

Keith_Richards [23]3 years ago
8 0

Answer:72

Step-by-step explanation:

8 × (3+7) can be written as 8 (3+7)

Now,simplify

8 (3+7)

8 (10)

8×10

80 is the answer.

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Helga [31]
Just use the word bank to fill in the blanks. Each letter they give you in the picture is the beginning of the words. So the first one to the left is a C______ and f_____ that would be Cold front.  Do the same for the others.
6 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
A school needs to buy new notebook and desktop computers for its computer lab. The notebook computers cost $275 each, and the de
xxTIMURxx [149]

The cost to buy 10 notebooks and 16 desktop computers is $5550

Cost of notebook computers = $275

Cost of desktop computers = $175 each

The cost to buy 10 notebooks and 16 desktop computers will be:

= 275(10) + 175(16)

= 2750 + 2800

= $5550

The cost to buy n notebooks and d desktop computers will be:

= 275(n) + 175(d)

= 275n + 175d

Read related link on:

brainly.com/question/23281416

8 0
2 years ago
$550 at 4% compounded daily for 13 years
vichka [17]

Answer:Sydney’s

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Solve the equation 3(2x + 2) = 3x - 15.<br> Ox=-7<br> 17<br> Ox=-<br> Ox=3<br> Ox=7
tatiyna

Simplify:

6x + 6 = 3x - 15

Now use all solutions

6(7) + 6 = 3(7) - 15

42 + 6 = 21 - 15

Nearly, you can tell it doesn't work.

6(-7) + 6 = 3(-7) - 15

-42 + 6 = -21 - 15

-36 = -36

So, -7 is x.

8 0
2 years ago
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