What volume of water at 4°c can be held in a cube whose edge is 3.0 cm long?

1 answer:

8 0

First density of water is 1 g/cm^3 (however changes in temperature changes it but we can ignore that)
and volume of this cube is 27 cm^3

You might be interested in

How far up does the ladder reach on the building?

pychu [463]

Step-by-step explanation:

The question missing attachment (incomplete)

But the question said how far up does the ladder reach on the building?

See the attachment

Let the tita be 60° and the height of the building be 50 meters

Now

Opposite/hypotenuse = sin(tita)

50/x = sin60°

Cross multiply to find x

x = 50/sin(60°)

x= 50/0.8660

x=57.7 meters

6 0

3 years ago

Read 2 more answers

Determine the equation of the line with slope −4 that passes through the point M(−2, 1).

scoray [572]

Y=mx+b
m=slope
b=y-intercept
y=-4x+b
Plug in the coordinate in place of x and y (-2,1)
1=-4(-2)+b
1=8+b
Subtract both sides by 8 to isolate B

b=-7

Final answer:
y = −4x − 7

5 0

3 years ago

Read 2 more answers

Help help help guys show you solution

Mars2501 [29]

Answer:

Step-by-step explanation:

1) y = 2x ----------(I)

x + y = 6 -----------(II)

Plug in y =2x in equation (II)

x + 2x = 6 {Add like terms}

3x = 6

x = 6/3

x = 2

Plugin x = 2 in (I)

y = 2*2

y = 4

Check:

LHS = x +y

= 2 + 4

= 6 = RHS

2)5x + 10y = 3 ------------(I)

x = (-1/2) y ------------(II)

Substitute x = (-1/2)y in (I)

$5*\frac{-1}{2}y + 10y = 3\\\\\frac{-5}{2}y+ \frac{10*2}{1*2}y = 3\\\\\frac{-5}{2}y+\frac{20}{2}y=3\\\\\frac{-5+20}{2}y = 3\\\\\frac{15}{2}y=3\\\\ y = 3*\frac{2}{15}\\\\ y = \frac{2}{5}$