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aleksklad [387]
3 years ago
5

if a minute hand on a clock turns 1 degree every minute, how many minutes have passed when it's 1/8 of the way around the clock?

Mathematics
1 answer:
Lynna [10]3 years ago
4 0
There's 60 min, so 1/8 of 60

60/8= 7.5 minutes in 1/8 of 60
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Two clocks are turned on at the same time. One clock chimes every 15 minutes. The
Kisachek [45]

Answer:

In 75 minutes, they will chime in together.

Step-by-step explanation:

First clock- 15, 30, 45, 60, 75

Second clock- 25, 50, 75

5 0
3 years ago
I need these three and they shouldn’t be too hard.
kondor19780726 [428]

Answer:

i dont know

Step-by-step explanation:

sorry my man my school is still just going into these kind of questions ):

4 0
3 years ago
A stocks value decreased the same amount each day for 4 days. If the total change in value was -2.5 what was the change each day
KIM [24]

Answer:

-0.625

Step-by-step explanation:

4 0
2 years ago
A group of workers can plant 5/8 acres in 4/5 days. What is the unit rate in acres per day?
Mila [183]
In order to find the unit rate of acres per day, or in other words, how many acres can they plant in one day, you must divide 5/8, the number of acres planted, by 4/5, the number of days it took to plant. When you divide the two fractions, first set up an expression:
5/8<span>÷4/5

Then, to make things simpler, turn the division expression into a multiplication statement so that you have 5/8*5/4. Then multiply straight across and you get your answer as 25/32. This means that the workers can plant 25/32 acres per day.</span>
3 0
3 years ago
Write the equation for a 3rd degree polynomial function that has roots at x = 1–3i and x = 2. The y‑intercept is (0,10). Write a
HACTEHA [7]

Answer:

\displaystyle P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)

Step-by-step explanation:

<u>Factored Form Of Polynomials </u>

If we know the roots of a polynomial as

\alpha _1,\alpha _2,\alpha _3

the polynomial can be expressed in factored form as

a(x-\alpha _1)(x-\alpha _2)(x-\alpha _3)

We are given two of the three roots of the polynomial:

\alpha _1=1-3i

\alpha _2=2

The other root must be the conjugate of the complex root:

\alpha _3=1+3i

Recall the product of two complex conjugate numbers is

(1-3i)(1+3i)=1^2-(3i)^2=1+9=10

The required polynomial is

P(x)=a\left[ x-(1-3i)\right ]\left[ x-(1+3i)\right ](x-2)

P(x)=a(x^2+2x+10)(x-2)

This is the factored form of the polynomial where only real numbers appear

We need to find the value of a, such as

P(0)=10

P(0)=a(0^2+2(0)+10)(0-2)=10

-20a=10

Thus the value of a is

\displaystyle a=-\frac{1}{2}

The expression of the required polynomial is

\boxed{P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)}

5 0
3 years ago
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