What is the inverse of 4 square

1 answer:

5 0

$a^{-1}=\dfrac{1}{a}-\text{the inverse of a}\\\\\text{the inverse of}\ 4^2:\\\\\left(4^2\right)^{-1}=4^{-2}=\dfrac{1}{4^2}=\dfrac{1}{16}$

You might be interested in

Find the measure or the missing angle, please

ExtremeBDS [4]

IK its an obtuse angleeee if that helps

3 0

3 years ago

Solve for x. Please help quick, it’s my last question for my test

Sladkaya [172]

Answer:

x = 9

Step-by-step explanation:

84 + (7x + 5) + (180 - (17x-1)) = 180

84 + 7x + 5 + (181 - 17x) = 180

270 + (-10x) = 180

90 = 10x

x = 9

3 0

3 years ago

How to solve this elimination

aleksandrvk [35]

Firstly you have to reduce the 4 variables to a double system of equation with only 2 variables.

Let's say, first we have to eliminate Z:
Take 1st & 3rd equation & multiply each term of the 1st by (- 1). One done you add up the 1st & the 3rd & you will get:
5W - 4x + 2y = - 18
Follow the same methodology to find another equation without z. Once done you will have a system of 2 equation with 2 variable easy to solve,

At the end you will find:
w = -3
x = -2
y = -1
z = 3

4 0

3 years ago

Help with question 4 please

Juliette [100K]

Answer: y=5 x=11

abc=def

ab=de <b=<e

17y-8=12+13y 11x-4=117

-13y -13y +4 +4

4y-8=12 11/11x=121/11

+8 +8 x=11

4/4y=20/4