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AVprozaik [17]
3 years ago
11

Hellllllllllllllllllllllllllllllllppppppppppppppppppppp

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

It would b ' A B F and G' the total number of pencils would be 274

Step-by-step explanation:

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Please help i’ll give brainliest
Mekhanik [1.2K]

Answer:

Organisms that break down dead or decaying organisms

Step-by-step explanation:

Hope this helps :b

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3 years ago
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I’m struggling on both of them can you give both answers
Leona [35]

4.16 hours and 4 cups

Step-by-step explanation:

10. To find the % of something simply turn 5/6 in to a decimal (.83) then times it by the number you want .83 * 60 = 50 so its about 50 min each class, just times it by 5 =250 and lastly divide it by 60 for hours <u>4.16</u>

11. Simply times it by 6, 2/3*6= <u>4</u><u> </u><u>c</u><u>u</u><u>p</u><u>s</u>

4 0
3 years ago
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2×1,000+9×100+5×1+1×1100+3×11,000
elixir [45]

Answer: I am not sure if this is correct but I got 2.431619300243096x10^22, 2.6746457133 x 10^13, and the the last one I also get 2.4316193 x 10^10. I AM NOT TO SURE IF I DID THIS CORRECT OR NOT, PLEASE DO NOT REPORT ME IF THIA IS WRONG, I TRIED TO HELP.

Step-by-step explanation: I AM NOT SO GOOD WITH MATH!!

3 0
3 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
3 years ago
I need help with this simple Geometry Question
Nostrana [21]

Answer: 132º

Step-by-step explanation:

Since <QSR is an inscribed angle, that means that the intercepted arc, which is arc QR, is twice the measure of that angle, which is 132º. Since <QPR is a center angle, it is equal to its center arc. So, <QPR is 132º.

8 0
3 years ago
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