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Ainat [17]
3 years ago
14

Simplify 10:11 as a ratio

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

Answer:

10:11

Step-by-step explanation:

10/11 is a reduced fraction, no common factors between the numerator and denominator, so this ratio is already simplified as far as we can go.

Leni [432]3 years ago
7 0

Answer: 10:11

10:11 is already simplified and can no longer be simplified. This is the lowest it can go as.

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PLZ HELP WITH THIS QUESTION!
Bad White [126]

Answer:

D

Step-by-step explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ± \sqrt{12^2-(4(-16)(-d))}) / - 32

 = ( - 12 ± \sqrt{144-64d}) / - 32

 = ( - 12 ± \sqrt{16(9-4d)}) / - 32

 = ( - 12 ± 4\sqrt{9-4d}) / - 32

 = \frac{-12}{-32} ± \frac{4}{-32}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{1}{8}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{\sqrt{9-4d} }{8} → D

8 0
3 years ago
Why did I get this question wrong?
Talja [164]

Answer:

9.25

Step-by-step explanation:

M₄ means the area using 4 rectangles with heights equal to the function evaluated at the midpoints.

The width of each rectangle is (4−0)/4 = 1.

The area of each rectangle is:

M₁ = (1) (1.12) = 1.12

M₂ = (1) (1.80) = 1.80

M₃ = (1) (2.69) = 2.69

M₄ = (1) (3.64) = 3.64

The total area is therefore:

M = 1.12 + 1.80 + 2.69 + 3.64

M = 9.25

7 0
3 years ago
A recent poll of 124 randomly selected residents of a town with a population of 310 showed that 93 of them are opposed to a new
Stolb23 [73]
What is even the question?
7 0
3 years ago
Read 2 more answers
Question 6 Unsaved Identify the slope and y-intercept of the graph of the equation. Then graph the equation. y = −5/4x+1
Lena [83]
Slope = -5/4
y intercept = 1

The slope is always attached to x. The intercept is the number attached on the end. 
4 0
3 years ago
The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis
Firdavs [7]

Answer:

sin\theta_1 =  - \frac{2\sqrt{70}}{19}

Step-by-step explanation:

We are given that \theta_1 is in <em>fourth</em> quadrant.

cos\theta_1 is always positive in 4th quadrant and  

sin\theta_1 is always negative in 4th quadrant.

Also, we know the following identity about sin\theta and cos\theta:

sin^2\theta + cos^2\theta = 1

Using \theta_1 in place of \theta:

sin^2\theta_1 + cos^2\theta_1 = 1

We are given that cos\theta_1 = \frac{9}{19}

\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{280}{361}\\\Rightarrow sin\theta_1 =  \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 =  +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}

\theta_1 is in <em>4th quadrant </em>so sin\theta_1 is negative.

So, value of sin\theta_1 =  - \frac{2\sqrt{70}}{19}

6 0
3 years ago
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