5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
<span>÷5 ÷5 </span>
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.
Answer:
idk how to do that try to slove it
but I didn't get right answer
Answer:
<h3>The ratio of technicians to all helpers is 11 : 7, or
or 11 to 7.</h3>
Step-by-step explanation:
- Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
- Let x be the number of ushers ( or helpers ).
- Therefore x=7 helpers.
- Let y be the number of technicians.
- Therefore y=11 technicians.
<h3>To find the ratio of technicians to all helpers :</h3>
That is to find the ratio of y to x.
We can write the ratio of technicians to all ushers(helpers) as y : x
Which implies that 11 : 7, (since y=11 and x=7)
Or or 11 to 7
<h3>The ratio of technicians to all helpers is 11 : 7, or
or 11 to 7</h3>
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
The Answer is <span>(x−2)</span><span>(3x+5<span>)</span></span>
