The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).
<h3>Which points among the answer choices represents the vertices of the ellipse whose equation is given?</h3>
The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.
Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;
(x-h)²/a² +(y-k)²/b² = 1.
Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.
Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).
The vertices in this scenario are therefore;
(7+8, -2) and (7-8, -2).
= (15, -2) and (-1, -2).
Read more on vertices of an ellipse;
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Answer is D {-8, -3, 5, 7 }
hope it helps
We could do it with algebra. But we can also do it the long way, which is
shorter than the algebraic way.
The digit in the tens place is 3 times the digit in the units place.
So the number MUST be
31, or
62, or
93 .
It can't be anything else.
Now here they are again, with the reverse of each one:
31 . . . 13 The new number is 18 less.
62 . . . 26 The new number is 36 less.
93 . . . 39 The new number is 54 less.
Obviously, the original number is 62.
Step-by-step explanation:
I think that X2 should be x squared
Answer:
(1, 1), (2, 2.333) and (3, 3.666).
Step-by-step explanation:
So, for x = 1, we have:
4*1 - 3y = 1
3y = 3
y = 1
For x = 2, we have:
4*2 - 3y = 1
3y = 7
y = 2.333
For x = 3, we have:
4*3 - 3y = 1
3y = 11
y = 3.666
The points we need to plot is (1, 1), (2, 2.333) and (3, 3.666).
