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stich3 [128]
4 years ago
13

Which of these properties of a rigid transformation is exclusive to translations?

Mathematics
2 answers:
crimeas [40]4 years ago
8 0
The properties of a rigid transformation is exclusive to translations is teh phrase "<span>The points in the preimage lie in the same plane as the points in the image". The rest of the statements do not answer the question above.</span>
vladimir1956 [14]4 years ago
5 0

Answer with explanation:

There are four kind of Rigid transformation that can take place in a two dimensional or Three dimensional geometrical Shape

1. Rotation

2. Reflection

3.Dilation

4. Translation

When we translate a geometrical shape , the Preimage , shifts from one position to another position in  the plane in which it lies ,without changing the shape ,size ,and Interior angle of the PreImage.  

→→I have described first three properties ,which are true to translation by taking a triangle ,having vertices , (0,0), (0,1) and (1,0).

Now, translating the triangle , by 1 unit right and 1 unit up,got the triangle having vertices, (1,1),(1,2) and (2,1).

Option 4 : The orientation of sequences of points in the pre image are always preserved, is the property of a rigid transformation that appears exclusive to translations.

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hompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 125 millimeters,
choli [55]

Answer:

P(-2.012

So since we want the probability that "the sample mean would differ from the population mean by greater than 2.2 millimeters". Then we use the complement rule and we got

P=1-0.9558=0.0442

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the  diameter of a population, and for this case we know the distribution for X is given by:

X \sim N(125,49)  

Where \mu=125 and \sigma=7

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(125,\frac{7}{\sqrt{41}}=1.093)

Solution to the problem

We can begin the problem finding this probability

P(\mu -2.2

We can use the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(125-2.2

=P(\frac{122.8-125}{\frac{7}{\sqrt{41}}}

And we can find this probability on this way:

P(-2.012

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-2.012

So since we want the probability that "the sample mean would differ from the population mean by greater than 2.2 millimeters". Then we use the complement rule and we got:

P=1-0.9558=0.0442

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