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3 years ago

If Angle A = 5x-10, find the value(s) for x that would ensure that Angle A was an obtuse angle.

Mathematics

1 answer:

morpeh [17]3 years ago

3 0

Answer:

20 < x < 38.

Step-by-step explanation:

An obtuse angle has a value between 90 and 180.

90 < 5x - 10 < 180

5x - 10 > 90

5x > 100.

x > 20.

5x - 10< 180

5x < 190

x < 38

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(Explanation)

Step-by-step explanation:

Part A:

The graph of y = $x^{2}$ + 2 will be translated 2 units up from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate left.

This is what graph A should look like:

[Attached File]

Part B:

The graph of y = $x^{2}$ - 2 will be translated 2 units down from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate right.

This is what graph B should look like:

[Attached File]

Part C:

The graph of y = 2 $x^{2}$ is a stretched version of the graph y = $x^{2}$ . Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

This is what graph C should look like:

[Attached File]

Part D:

The graph of y = $\frac{1}{2}x^{2}$ is a compressed version of the graph y = $x^{2}$ . Numbers that are in-between 0 and 1, and -1 and 0 are compressed.

This is what graph D should look like:

[Attached File]

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Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$