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andrezito [222]
3 years ago
12

NEED URGENT HELP

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer: Tv is an examle watching a work out video or maybe if your talking about how has it affected people over the years than sitting around and watching that,  now lets get an example about phones. Phones are really affecting to sports you can be addicted to the phone. Hoped this helped!

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MRS.Bonnette's recipe for banana bread calls for 3 and one fourths cups of sugar. She wants to make 6.5 batches so that she has
densk [106]

Answer:

21/ \frac {1}{8}

Step-by-step explanation:

Since we're given that a batch requires 3 and one fourths cups of sugar, this is written as

3/ \frac {1}{4}

If she wants 6.5 batches then we just cross multiply

1 batch=3/ \frac {1}{4}

6.5 batches=x

X=6.5\times 3/ \frac {1}{4}

X=6/ \frac {1}{2}\times 3/ \frac {1}{4}

X=\frac {13}{2}\times \frac {13}{4}

X=\frac {169}{8}

X=21/ \frac {1}{8}

6 0
3 years ago
Selena and Drake are evaluating the expression , when . Selena's Work Drake's Work Who is correct and why? Selena is incorrect b
Shtirlitz [24]

Answer:

Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.

I did this lesson i asked my teacher to help me but i did this problem on my own so i hope its right :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex
enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) ×  (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by \dfrac{2}{3}.

8 0
3 years ago
Which equation represents exponential decay?
MAVERICK [17]
Y=(1/5)^x would be the only equation demonstrating decay of these
6 0
3 years ago
How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)&gt;0
scZoUnD [109]

Answer:

  x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

  x = -3 . . . sign change from + to -

  x = -1 . . . graph touches, but no sign change. - on either side of x=-1

  x = 4 . . . sign change from - to +

__

The function will be positive for x < -3 and for x > +4.

_____

<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

3 0
2 years ago
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