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3 years ago

Solve for x. mx2 + y e = b

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

X= square root be-y/m

m_a_m_a [10]3 years ago

7 0

X=(b/2m)*y-e is the answer I believe.

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Help me pls lol lollll

stiks02 [169]

Answer:

hope I got this right it's been a while

Step-by-step explanation:

-15n^4t^6y^5

8 0

3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago

Data was collected from a simple random sample of 200 cell phone users age 18 or older in the United States. Each user was categ

frutty [35]

Answer:

Step-by-step explanation:

i took it

6 0

3 years ago

Read 2 more answers

An account is opened with $7,595.96 with a rate of 2%

olganol [36]

The answer is right above me yw lol

3 0

3 years ago

46 out of 200 dogs are short haired breeds. What percent of dogs are not short haired breeds

Ivahew [28]

Hi!

46 out of 200 are short haired, which means that 200 - 46 = 154 out of 200 are not short haired. In percentages, that is:

154/200 = 77/100 = 77%

Hope this helps!

8 0

3 years ago