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eimsori [14]
3 years ago
7

E^(x/2) /(e^(x/3) +1)

Mathematics
1 answer:
nevsk [136]3 years ago
8 0

\int e^{x/2} /(e^{x/3} +1) dx

start with substituting z=e^x

z=e^x\\dz=e^x dx\\\int \frac{dz}{z^{5/6}+z^{1/2}}

then substitute u = z^(1/6):

u=z^{1/6}\\dz=6 z^{5/6}du\\6 \int \frac{u^2}{u^2+1}du

that integral has a standard form that can be looked up in integral tables, it has the following solution:

6(u - \tan^{-1} u) + \mbox{constant}

substituting back the the variable z and then x you get the final solution:

6 e^{x/6} - 6 \tan^{-1}(e^{x/6}) + \mbox{constant}

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Answer:

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A local diner must build a wheelchair ramp to provide handicap access to the restaurant. Building codes require that a wheelchai
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Answer:

  A) 1/20

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A) Slope is the ratio of rise to run, so is ...

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  slope = 1/20

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B) The maximum height is 1/20 of the horizontal distance, so ...

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4 0
3 years ago
A rectangle is 6 units wide and x-8 units long. It has the same area as a triangle with the height of 7 units and a base of x-3
Snowcat [4.5K]
AREA OF A RECTANGLE IS 42 UNITS

Rectangle:                             Triangle: 
A = L * W                             A = hb / 2
A = (x-8) * 6                         A = (7(x-3)) / 2
A = 6x - 48                            A = (7x - 21) / 2

Since the problem states that both rectangle and triangle have the same area.Then:

6x - 48 = (7x - 21) / 2

1) Eliminate the denominator 2 by multiplying both sides by 2.

2 * (6x - 48) = 2 * ((7x - 21) / 2)
12 x - 96 = 7x - 21

Find x. Transfer like numbers and change their signs.

12x - 7x = 96 - 21
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Substitute x by its value:

Rectangle:                            Triangle
A = (x-8) * 6          -                A = (7(x-3)) / 2                      Areas of both Rectangle
A = (15 -8 ) * 6                       A = (7(15-3)) / 2                      and Triangle is the same.
A = 7 * 6                                  A = (7 * 12) / 2
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5 0
3 years ago
Write a real world problem that can be modeled by 4 × (-7)
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4 × (-7)= -28
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7 0
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Answer:

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