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lozanna [386]
3 years ago
9

Which data point is an outlier in this graph?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

I can't find the answer.

Step-by-step explanation:

You should put a photo of the graph and I would be able to tell :)

Sorry

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(X-5)^2=0<br><br> Solve for x
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Point A is located at (5, 10) and point B is located at (20, 25).
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Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at  a ratio of 7, thus 3:7,

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\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)&#10;\\\\\\&#10;C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10}  \right)&#10;\\\\\\&#10;C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2}  \right)
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We can treat each distance distance traveled by the four wheelers are vectors. Their sum must be zero since the last four wheeler truck ends up where the first four wheeler truck started
d1∠1 + d2∠2 + d3∠3 + d4∠4 + d5∠5 = 0
d5∠5 = - (d1∠1 + d2∠2 + d3∠3 + d4∠4)
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The fifth wheeler must travel at an angle of -10 degrees.
8 0
3 years ago
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