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Mariana [72]
3 years ago
6

Help me out here please

Mathematics
1 answer:
Maslowich3 years ago
7 0
4 5 8 11

5+8/2 = 6.5

Hope this helps!
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R Problem Old Faithful is a geyser located in Yellowstone Nation Park in Wyoming. It received the name "Old Faithful" by the Was
Tpy6a [65]

Answer:

Step-by-step explanation:

The first 6 rows of the eruptions data :

eruptions waiting

1 3.600 79

2 1.800 54

3 3.333 74

4 2.283 62

5 4.533 85

6 2.883 55

R code :

1. You can directly access the "Faithful" data in R without importing the data. The dataset faithful is present in the R or you can load the datasets. or use install the datasets.load. package

If you have the data in a text file, make sure all the columns and rows are separated by commas

Step 1: open notepad

Step 2: enter data with no spaces but only commas

Step 3: save the file as ‘faithful.txt’ on your Desktop

# Get R help

?read.table

# Import the data

rain<-read.table("C:/Users/YOUR-NAME/Desktop/faithful.txt", header = TRUE,

                  sep = ",")

Check the data

data("faithful") #Loading Faithful data

head(faithful, 6) #Reading first 6 rows of the data

8 0
3 years ago
hi friends..please help me..it's very urgent... please give the solutions of the given bits... please....​
Komok [63]
Hey I don’t know much of this but I really recommend you to re ask this question but choose the other option to talk to an expert :)
3 0
3 years ago
Hey can someone help:)?​
Zolol [24]
I think it’s the first one
7 0
3 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
3 years ago
2(x + 4) - 5 = 3x + 3
OverLord2011 [107]

Answer:

x=0

Step-by-step explanation:

2(x+4)- 5 = 3x+3

Distribute

2x+8-5 = 3x+3

Subtract x values

8-5 = x+3

3 = x+3

Final Subtraction

x = 0

3 0
3 years ago
Read 2 more answers
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