Solve for x. X/4+1=3?

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

Subtract 1: x/4=2 multiply by 4: x=8 which is the answer

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Describe the pattern in the following sequence and list the next three terms:

balu736 [363]

Answer:

4×2=8

8×2=16

16×2=32

32×2=64

64×2=128

128×2=256

I HOPE THIS HELPS U

5 0

3 years ago

Read 2 more answers

Please solve both of these questions

Alex

Answer:

jane will arrive at 3:41

Mira will arrive at 3:50

so the the difference in time is 9 minutes

—————-

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7 0

3 years ago

What is the common ratio of the sequence?

Murljashka [212]

6/-2 = -18/6 = -3

The appropriate choice is ...
A) -3

6 0

3 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum: