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Harrizon [31]
3 years ago
6

The area of a square floor on a scale drawing is 49 square centimeters, and the scale drawing is 1 centimeter:4 ft. What is the

area of the actual floor? What is the ratio of the area in the drawing to the actual area? The area of the actual floor is square feet. The ratio of the area in the drawing to the actual area is 1 square centimeter: square feet.
Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

  1. 784 ft²
  2. 1 cm² : 16 ft²

Step-by-step explanation:

Since we need the ratio of drawing area to floor area to figure the actual floor area, it is convenient to answer the questions in reverse order.

The ratio of drawing area to actual area is ...

... ((1 cm)/(4 ft))² = (1 cm²)/(16 ft²)

____

Then the actual floor area is ...

... (16 ft²)/(1 cm²) = actual area/(49 cm²)

Multiplying by 49 cm² gives ...

... (16 ft²)*49/1 = actual area = 784 ft²

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<u>Sheet 1: Question 3</u>

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<u>Sheet 1: Question 4</u>

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Angle POQ = 130° <em>(because it is vertically opposite to angle SOR)</em>

<u>Sheet 1: Question 6</u>

Angle 1 = 72° <em>(because vertically opposite angles)</em>

∠4 + ∠1 + 41 = 180° <em>(because all angles on a straight line are equal to 180°)</em>

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° <em>(because vertically opposite angles)</em>

∠2 = 67° <em>(because vertically opposite angles)</em>

<u>Sheet 2: Question 3</u>

Step 1: Find the value of x

<em>Sum of complementary angles is equal to 90°</em>

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

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<u>Step 2: Find angle A and angle B using x</u>

Angle A: 7x + 4

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Angle A = 53°

Angle B: 4x + 9

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Angle B = 37°

<u>Sheet 3: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>Sum of supplementary angles is equal to 180°.</em>

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 3x - 7

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Angle B: 2x + 2

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Angle B = 76°

<u>Sheet 3: Question 4</u>

<em>Sum of supplementary angles is equal to 180°.</em>

<u>Step 1: Find x</u>

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

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48x = 768

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1/4[36(16)-8] = 568/4

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Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

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<u>Sheet 4: Question 1</u>

<em>All angles on a straight line are equal to 180°</em>

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

<u>Sheet 4: Question 2</u>

Linear pair 1: 5 and 7 <em>(because both angles are on a straight line and are equal to 180°)</em>

Linear pair 2: 6 and 8<em> (because both angles are on a straight line and are equal to 180°)</em>

<u>Sheet 4: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>All angles on a straight line are equal to 180° or linear pairs are equal to 180°</em>

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

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x = 12.5

<em>Step 2: Find angles using the value of x</em>

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

<u>Sheet 4: Question 4</u>

<em>Linear pairs are equal to 180°.</em>

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

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[2(27x-6) + 3(6x-20)]/6 = 180

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72x - 72 = 1080

72x = 1152

x = 16

!!

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4 years ago
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