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3 years ago

Perform the indicated operation. 12 ÷ (-6) 6 -18 -2 -72

Mathematics

2 answers:

ioda3 years ago

8 0

-2 because you are dividing by a negative which makes the answer the same.

12/6 is 2 and since it’s negative it’s -2

Alex3 years ago

7 0

Answer:

the answer is -2 because positive divided by a negative is equals to a negative so positive 12 divided by -6 it will be equal to -2

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How are unit rates and equevlent ratios related

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2 years ago

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andriy [413]

Answer:
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3 years ago

Solve please<br> A. 1/6m-3=-5<br> B. 2/3x-3=1/2x-7<br> C. x+x/2-4=x/4

AysviL [449]

Answer:

A m = 48

B x = -24

C x = 16

Step-by-step explanation:

A. 1/6m - 3 = 5

1/6m = 5+3

1/6m = 8

multiply both side by 6

m = 8×6

m = 48

B. 2/3x-3 = 1/2 x-7

2/3 x - 1/2 x = -7 +3

1/6 x = -4

multiply 6 to the both side

x = -4×6

x= -24

C.x+x/2-4= x/4

x+x/2 - x/4 = 4

x + l/2 x - 1/4 x = 4

1/4 x = 4

multiply both side by 4

x= 4×4

x = 16

4 0

2 years ago

debra buys a new mountain bike for 750 dollars . Sales tax is 9% . how much does Debra actually have to pay ?

Georgia [21]

Answer:

$817.50

Step-by-step explanation:

Hello Matt7151!

To find the total amount, we will first need to find how much tax.

We can express 9% as the fraction $\frac{9}{100}$ .

$\frac{9}{100}$ × 750 = 67.50

So she's paying $67.50 sales tax.

750.00

67.50

-------------------

817.50

So Debra's really paying $817.50.

Thus, the answer is $\boxed{$817.50}$$ $\boxed{817.50}$ .

5 0

3 years ago

CALCULUS EXPERT WANTED. Can someone solve this or at least try to explain to me the fundamental theorem of calculus (FTC).

Amanda [17]

a. By the FTC,

$\displaystyle\frac{\mathrm d}{\mathrm dx}\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=(\cos x+\sqrt{\cos x})\dfrac{\mathrm d}{\mathrm dx}\cos x=-\sin x(\cos x+\sqrt{\cos x})$

b. We can either evaluate the integral directly, or take the integral of the previous result. With the first method, we get

$\displaystyle\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=\dfrac{t^2}2+\dfrac{2t^{3/2}}3\bigg|_{t=1}^{t=\cos x}=\left(\dfrac{\cos^2x}2+\dfrac{2(\cos x)^{3/2}}3\right)-\left(\dfrac12+\dfrac23\right)$

$=\dfrac{\cos^2x}2+\dfrac{2\sqrt{\cos^3x}}3-\dfrac76$

c. The derivative of the previous result is

$\dfrac{2\cos x(-\sin x)}2+\dfrac{2\cdot\frac32(\cos x)^{1/2}(-\sin x)}3=-\sin x\cos x-\sin x\sqrt{\cos x}$

which is the same as the answer given in part (a), so ...

d. ... yes

4 0

3 years ago