If the radius is 25, the diameter is 50.
Use C = (3.14)(50)
C = 157
No need round off to the nearest tenth.
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
We would need 3 points for an equilateral triangle, 5 for a pentagon, and 6 for a hexagon, which do not fit the current steps.
Answer:
15 routes
Step-by-step explanation:
3 x 5 = 15 routes
The number is -11/4 less than -8/3
