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3 years ago

the equation of line k is y=1/5x-1/8. what equation of the line that is perpendicular to line k and passes through (0,0)

1 answer:

4 0

The slope of a perpendicular line is the negative reciprocal of the normal slope. For example, 3/7 would become -7/3.

Because the slope of this line is 1/5, the slope of a line that is perpendicular to it is -5.

Now, to find the equation of the line, we need to find the y intercept. Since the line passes through (0,0), that is the y intercept. Now, we can make the equation of the line.

y = -5x

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I'd appreciate the help, its making my brain hurt plus i never was good at algebra

Andrei [34K]

Answer: I got -2

I plugged -6 in for y and then simplified. -6 x -6 = 36. 7 x -6 = -42. So 36 - 42 = -6. -6 + 4 = -2

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2 years ago

What is the perimeter of a square with a side whose length is x + 4?

Novosadov [1.4K]

Answer:

4x+16

Step-by-step explanation:

Just multiply x and 4 by 4 to get your answer.

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2 years ago

Solve for x in the equation x^2+11x

suter [353]

Answer:

Pretty sure it would be the last one.

Not sure if you want me to do the work. All I can say is that it would be very long.

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2 years ago

Read 2 more answers

← How many solutions does this linear system have y = x+2 6x - 4y = -10

defon

Answer:

This linear system has one solution.

Step-by-step explanation:

First equation: y = x + 2

Second equation: 6x - 4y = -10

Let's change the second equation in slope-intercept form y = mx + b.

Slope-intercept form

y = mx + b

m ... slope

b ... y-intercept

$6x - 4y = -10$

$6x + 10 = 4y$

$\frac{6}{4}x + \frac{10}{4} = y$

$\frac{3}{2}x + \frac{5}{2} = y$

If two lines have the same slope but different y-intercept, they are parallel - system has no solutions.

If two lines have the same slope and the same y-intercept, they are the same line and are intersecting in infinite many points - system has infinite many solutions.

If two lines have different slopes then they intersect in one point - system has one solution.

We see that lines have different slopes. First line has slope 1 and the other line has slope $\frac{3}{2}$ . So the system has one solution.

You can also check this by solving the system.

Substitute y in second equation with y from first.

6x - 4y = -10

6x - 4(x + 2) = -10

Solve for x.

6x - 4x - 8 = -10

2x = -2

x = -1

y = x + 2

y = -1 + 2

y = 1

The lines intersect in point (-1, 1). <-- one solution

8 0

1 year ago

For the function given, state the middle line; f(t) = 40cos (80t + 20)

Digiron [165]

In the standard form of the equation

$\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\$

The middle line =k

For our given problem

f(t) = 40cos (80t + 20)

On comparison we get k=0

Hence middle line=0

8 0

2 years ago