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VikaD [51]
4 years ago
7

Seven more than the quotient of a number and 2 is 10.

Mathematics
1 answer:
siniylev [52]4 years ago
5 0

Answer: n = 5

Step-by-step explanation:

7 + n/2 = 10

Subtract 7 from 7 and 10

n/2 = 3

divide 2 from n/2 and 10

n/2 divided by 2 equals

n = 10

10/2 = 5

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A picture can help.

The median to the long side divides the isosceles triangle into two right triangles with hypotenuse 10 and short leg 6. Thus the long leg (median of interest) is found by the Pythagorean theorem to be

... √(10² -6²) = √64 = 8

Then the midpoint of the short side is found to be 6 + (6/2) = 9 units to the side and 8/2 = 4 units above the opposite vertex. Hence the square of the length of that median is 9² + 4² = 97.

The sum of squares of interest is

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3 years ago
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Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

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\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
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Eva8 [605]

Answer:

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The answer to your question is the first graph in the second line.

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