What is the relationship between segment ED and segment AC?

1 answer:

6 0

D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
2-EB=EA E midpoint of AB 
DB=DC D midpoint BC ...............> ED=AC/2=2 
3-T midpoint of SR 
U midpoint of QR ---------> TU = QS/2 
QS=2 TU = 4.4 
4- The same steps SR=2 UV=9 
5-N midpoint of KM 
O midpoint of ML 
* NO parallel to Kl

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{14 x - 4 y = 74 | (equation 1)
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