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3 years ago

The ratio of Tom's studying time on a weekday to his studying

Mathematics

2 answers:

lesantik [10]3 years ago

6 0

Answer:

6 hrs

Step-by-step explanation:

4:5

2.4 : 3.2

2.4+3.2=6 hrs

Helen [10]3 years ago

3 0

Answer

6 hours

Explanation

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A flagpole has a height of 16 yards. It will be supported by three cables, each of which is attached to the flagpole at a point

Marta_Voda [28]

Cables are forming 3 right angled triangles the pole being the shared height of them;

(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);

a^2 + b^2 = c^2

12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;

1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45

Add them up = 84yd of cable needed

8 0

3 years ago

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Hello, precalc, need help on finding csc

Ainat [17]

Recall the double angle identity for cosine:

$\cos(2x) = \cos^2(x) - \sin^2(x) = 1 - 2 \sin^2(x)$

It follows that

$\sin^2(x) = \dfrac{1 - \cos(2x)}2 \implies \sin(x) = \pm \sqrt{\dfrac{1-\cos(2x)}2} \implies \csc(x) = \pm \sqrt{\dfrac2{1-\cos(2x)}}$

Since 0° < 22° < 90°, we know that sin(22°) must be positive, so csc(22°) is also positive. Let x = 22°; then the closest answer would be C,

$\csc(22^\circ) = \sqrt{\dfrac2{1-\cos(44^\circ)}} = \sqrt{\dfrac2{1-\frac5{13}}} = \dfrac{\sqrt{13}}2$

but the problem is that none of these claims are true; cot(32°) ≠ 4/3, cos(44°) ≠ 5/13, and csc(22°) ≠ √13/2...

3 0

2 years ago

Write these as normal numbers.

ELEN [110]

Answer:

a) 510000000 c) 24.4 d) 502.3

Step-by-step explanation:

7 0

3 years ago

3c-d=T<br> Could you<br> solve for c

RSB [31]

- - Let's solve for C.

Starting off with our equation:
$3c+d=T$

Transform:
$3c=T+D$

Solve for that:
$\frac{3c}{3} = \frac{T+D}{3}$

Solve for that for the last time and your answer is $\frac{T+D}{3} =C$

7 0

3 years ago

Read 2 more answers

Somebody pls help me!!!

Setler [38]

<h3>Answer: 60 units</h3>

=====================================================

Explanation:

The similar red marks on the angles tell us those angles are congruent. So they are the same measure.

The sides opposite those congruent angles are the same length. This means AC = BC. This triangle is isosceles.

--------------

Solve for x

AC = BC

5x-8 = 2x+7 .... substitution

5x-8-2x = 7 ... subtract 2x from both sides

5x-2x = 7+8 ..... add 8 to both sides

3x = 15

x = 15/3 ... divide both sides by 3

x = 5

---------------

Use that x value to compute each side length

AB = 3x+11 = 3*5+11 = 15+11 = 26

BC = 2x+7 = 2*5+7 = 10+7 = 17

CA = 5x-8 = 5*5-8 = 25-8 = 17

Note how BC and CA are the same length (17 units). This helps confirm we have the right x value.

----------------

The last step is to add up all the side lengths to get the perimeter

perimeter of triangle = sum of all the sides

perimeter of triangle = side1 + side2 + side3

perimeter of triangle ABC = AB + BC + CA

perimeter of triangle ABC = 26 + 17 + 17

perimeter of triangle ABC = 60 units

4 0

2 years ago

Read 2 more answers