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3 years ago

F(x) = 2x^2 Find f(-3)

Mathematics

2 answers:

Leokris [45]3 years ago

6 0

Answer:

Step-by-step explanation:

f(x)=2x^2

f(-3)=2(-3)^2

f(-3)= -6^2

f(-3)=36

guapka [62]3 years ago

4 0

Answer:

Step-by-step explanation:

f(x) = 2 x^2

f(-3) means that wherever there is an x on the right, put in - 3

f(-3) = 2 (-3)^2

(-3)^2 = 9

f(-3) = 2 * 9

f(-3) = 18

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Select all of the number that round to 4.3 when rounded to the nearest tenth

faltersainse [42]

Answer:

4.29-4.28-4.27-4.26-4.25

Step-by-step explanation:

6 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Don’t steal points Pls I’m doing a final need it quickly

Tcecarenko [31]

Answer:

the 3rd one

Step-by-step explanation:

A proportional relationship has to have a Stright line. Hope this helps :)

4 0

2 years ago

Read 2 more answers

When 250 students were interviewed, 96 of the students thought USC was the best school in the nation. The probability that one o

melomori [17]

Answer:

240/96.

Step-by-step explanation:

250-96 =240 so that's 240/96

3 0

3 years ago

Help me with number 10 please !!

mel-nik [20]

Um idk if its right but i think
s would be -3,6
r -5,3

6 0

3 years ago