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3 years ago

F(x) = 2x^2 Find f(-3)

Mathematics

2 answers:

Leokris [45]3 years ago

6 0

Answer:

Step-by-step explanation:

f(x)=2x^2

f(-3)=2(-3)^2

f(-3)= -6^2

f(-3)=36

guapka [62]3 years ago

4 0

Answer:

Step-by-step explanation:

f(x) = 2 x^2

f(-3) means that wherever there is an x on the right, put in - 3

f(-3) = 2 (-3)^2

(-3)^2 = 9

f(-3) = 2 * 9

f(-3) = 18

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Find the sizes of unknow angles of this triangle

Volgvan

<h2><u>Answer:</u></h2>

To determine to measure of the unknown angle, be sure to use the total sum of 180°. If two angles are given, add them together and then subtract from 180°. If two angles are the same and unknown, subtract the known angle from 180° and then divide by 2.

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2 years ago

Which value of m is a counterexample for the following statement?

Burka [1]

Answer:

Step-by-step explanation:

because 3 is a prime number and 3+2=5 which is also a prime number

6 0

3 years ago

PLEASE HELP IM SO STUCK 20 POINTS

prohojiy [21]

Answer: X = 2

Step-by-step explanation: The correct answer to this question is that x=2. Regardless of what point you go to on the line, it always has a value of 2 because it is going vertically (up and down) at 2.

5 0

3 years ago

PLEASE ANSWER ASAP!!!!

Arlecino [84]

We'll use the notation $\textrm{Arcsin } x$ for the principal value and $\arcsin x$ for all the values:

$\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k$

Part I

$\sin(\theta/2) = \frac 1 2$

$\theta/2 = \arcsin \frac 1 2$

Part II. In our range we can write

$\sin(\theta/2) = \sin(\frac \pi 6)$

$\theta/2 = \frac \pi 6 \textrm{ or } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}$

Part III.

$\theta = \frac \pi 3 \textrm{ or } \theta = \frac{5\pi}{3}$

Part IV.

$\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k$

$\theta = \frac \pi 3 + 4 \pi k \textrm{ or } \theta = \frac{5 \pi}{3} + 4\pi k \quad \textrm{integer } k$

5 0

3 years ago

Solve for x<br> x + y = 1<br> x + 7y = -4<br> 2x - 6y = 4<br> 5x + 15y = -10<br> 2x + 6y = 10

Arada [10]

X + y = 1
add - y both sides
x + y + - y = 1 + - y
x = - y + 1
Answer: x = - y + 1
Graph: y = - x + 1

x + 7y = - 4
add - 7 both sides
x + 7y + - 7y = - 4 + -7y
x = - 7y - 4
Answer: x = - 7y - 4
Graph: y = 0.142857x - 0.571429

2x - 6y = 4
add 6y to both sides
2x - 6y + 6y = 4 + 6y
2x = 6y + 4
divide both sides by 2
2x/2 = 6y + 4/2
x = 3y + 2
Answer: x = 3y + 2
Graph: y = 0.333333x - 0.666667

5x + 15y = - 10
add - 15 to both sides
5x + 15y + - 15y = - 10 + - 15y
5x = - 15y - 10
divide both sides by 5
5x/5 = - 15y - 10/5
x = - 3y - 2
Answer: x = - 3y - 2
Graph: y = - 0.333333x - 0.666667

2x + 6y = 10
add - 6y to both sides
2x + 6y + - 6y = 10 + - 6y
2x = - 6y + 10
divide both sides by 2
2x/2 = - 6y + 10/2
x = - 3y + 5
Answer: x = -3y + 5
Graph: y = - 0.333333x + 1.666667

Hope that helps!!!

8 0

3 years ago