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harina [27]
3 years ago
6

Can someone remind me how to do this again?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

This the formula for the Pythagorean Theorem.

Step-by-step explanation:

This is the formula for the Pythagorean Theorem but its written in a different way but it will give you the same answer.

So first you will be given two sides which will be represented as leg a and leg b.

So you would plug in the two numbers in the equation c = square root of 18^2 + 12^2

Now you would find 18^2 which equals 324

Then you would find 12^2 which equals 144

Add them together and get 468

To get what c equals or the hypotenuse you have to find the square root of 468.

The square root of 468 is 21.633 but you round it to the nearest tenth and get 21.6

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- 22 - 7v = - 3(8V + 4)<br> Round to the nearest hundreth
Dmitriy789 [7]

Answer:

v = 0.58

Step-by-step explanation:

-22 - 7v = -3(8v + 4)

Expand -3(8v + 4)

3 * 8v - 3 * 4

Simplify -3 * 8v -3 * 4

= -24v - 12

-22 - 7v = -24v - 12

Add 22 to both sides

-7v = -24v +10

Add 24v to both sides

17v = 10

\frac{17v}{17} =\frac{10}{17}

v =\frac{10}{17}

v=0.58

5 0
3 years ago
PLEASE DONT SKIP<br><br><br> show all work
neonofarm [45]

Answer:

i don't see nothing

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°
Iteru [2.4K]

Answer:

The answer to your question is: the first option  - 9/ \sqrt{80}

Step-by-step explanation:

Process

          cosФ = adjacent side / hypotenuse

          -1/9 = adjacent side / hypotenuse

          adjacent side = -1    hypotenuse = 9

          c² = a² + b²

          b² = c² - a²

           b² = 81 - 1

           b = \sqrt{80} \\    b = opposite side

But b is negative because we are in the third quadrant.

          b = -\sqrt{80}

Finally   csc Ф = hypotenuse / opposite side

             csc Ф = - 9 / \sqrt{80}

4 0
3 years ago
6(x+4)-(x+3)&gt;x-1 solve the inequality
Papessa [141]
The answer should be 4x+ 17 > x - 1
5 0
3 years ago
Please help stuck on question
vazorg [7]

Answer:

Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}

We can write this polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

such that the terms:

(x - x₁), (x - x₂), etc...

are called the factors.

In this case, we know that the roots OF THE FACTORS

are:

(x = - 2)

(x = - (1 + √5))

(x = + 3i)

If the root of the polynomial is  x = -2, then the factor should be:

(x + 2)

which is zero when we evaluate x in -2

Then the correct option is the first one.

5 0
2 years ago
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