Angle AOB + angle BOC = angle AOC
7x + 30 + 9x + 42 = 104
16x = 104 - 72
16x = 32
x = 2 degrees
Angle BOC = 9x + 42 = 18 + 42 = 60 degrees
let's find the equation of line passing through those two points.
slope of the given line :
now, let's plug the value of slope (m)
and y - intercept (c) in general equation
of line in slope intercept form.
i.e y = mx + c
so, we get the equation of given line as :
Answer:
Mean:
a) 4
b) 2
c) 2
d) 2
Median:
a) 4,2
b) 5,2
c) 5,1
d) 4,1
Mode:
a) 1
b) 1
c) 1
d) 1
Step-by-step explanation:
Mean:
a) 1+4+2+1 = 8/4=4
b)1+5+2+1 = 9/4= 2.25 (round to the nearest whole number = 2)
c) 1+5+1+0 = 7/4 = 1.75 (round to the nearest whole number = 2)
d) 1+4+1+0 = 6/4 = 1.5 (round to the nearest whole number = 2)
I do not know what to answer here can you repost this question and make it a little bit more clear as i am sure it is really confusing to everybody else as it stands right now<span />
<h3>
Answer: 5</h3>
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Explanation:
Vertex form is
y = a(x-h)^2 + k
We are told the vertex is (3,-2), so we know (h,k) = (3,-2)
y = a(x-h)^2 + k will update to y = a(x-3)^2 - 2
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Then we also know that (x,y) = (4,3) is a point on the parabola. Plug those x and y values into the equation and solve for 'a'
y = a(x-3)^2 - 2
3 = a(4-3)^2 - 2
3 = a(1)^2 - 2
3 = a - 2
3+2 = a
5 = a
a = 5
This is the coefficient of the x^2 term since the standard form is y = ax^2+bx+c.
