Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
Answer:
C
Step-by-step explanation:
Answer:
B) 18 ft
Step-by-step explanation:
The scale is 1 in. model : 6 ft real.
6/1 = 6
To go from model size to real size, multiply the model size by 6 and change from inches to feet.
3 in. model = 3 × 6 ft = 18 ft
15-(3•4) = m
m=how many markers Tim has left.
Answer: Option D.
Step-by-step explanation:
this is a quadratic equation of the form:
y = ax^2 + bx + c
First, things you must see.
The graph opens up, so we must have thata a is greater than zero, so we can discard the first option.
Second, we can see that the vertex is located in x ≈ 70
The vertex of a quadratic equation is: x = -b/2a
so we have:
70 = -b/2a
let's try our options and see if we can discard other:
B:
-b/2a = 69.9/2 = 34.95
we can discard this option.
C:
-b/2a = 78/2 = 39 we can discard this option.
D:
-b/2a = 69.9/2*0.5 = 69.9
This is the only one that fits, so this is the correct option.
