We first determine the z-scores for the given x-values of 64 and 96.
For x = 64: z = (64 - 80) / 8 = -2
For x = 96: z = (96 - 80) / 8 = 2
Therefore we find the probability that -2 < z < 2, which is around 0.95. Therefore, out of 100 students, approximately 100(0.95) = 95 students will weigh between 64 and 96 pounds.
Answer:
Step-by-step explanation:
14=r-9
+9
23=r
The answer is x=5 or x=1/2.
There are 6 pockets all together. You checked two of them and it wasn't
there. So you can forget about those 2, and now there are 4 pockets left.
The total number of ways for your next try is 4.
The number that will be successful is 1.
The probability of success on the next one is <em>1/4 = 25% .</em>
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Another method of solution, somewhat more complex:
Total number of pockets = 6.
Amount of money missing = $10
First partial sum, i.e. sum of numbers
in the first part of the problem = 6 + 10 = 16.
Total number of pockets = 6
Current value of cargo pants on a fashion scale from 1 to 10 = -2.
Second partial sum = 6 - 2 = 4.
Probability = (second partial sum) / (first partial sum) = 4/16 = <em>25% </em>.
Answer:
C) 384
Step-by-step explanation:
A=bh
