This question is incomplete, the complete question is;
X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)
Answer:
P( W> 10) is 0.1587
Step-by-step explanation:
Given that;
X ⇒ N( 13.9, 5.2 )
Y ⇒ N( 6.9, 3.8 )
W = X - Y
Therefore
E(W) = E(X) - E(Y)
= 13.9 - 6.9 = 7
Var(W) = Var(X) + Var(Y) -2COV(X.Y)
[ COV(X,Y) = 0 because they are independent]
Var(W) = 5.2 + 3.8 + 0
= 9
Therefore
W ⇒ N( 7, 9 )
so
P( W > 10 )
= 1 - P( W ≤ 10 )
= 1 - P( W-7 /3 ≤ 10-7 /3 )
= 1 - P( Z ≤ 1 ) [ Z = W-7 / 3 ⇒ N(0, 1) ]
from Standard normal distribution table, P( Z ≤ 1 ) = 0.8413
so
1 - P( Z ≤ 1 ) = 1 - 0.8413 = 0.1587
Therefore P( W> 10) is 0.1587
The length is 2 feet more than the width so L = w+2
so volume = (w+2) * w * 6
use distributive property:
(w*w + 2*w) * 6 =
(w^2+2w) *6 =
use distributive property again:
w^2 *6 + 2w*6 =
6w^2 +12w
Answer:
1 day ago — Find an answer to your question What least number must be subtracted from 5650 to get a perfect square? Also find the square root of this ...
Step-by-step explanation:
(-16,7)
K=5 which makes y=0
Plug in -16 for x which means y=7
Therefore, - 16,7 will be the value of x,y that has no solution.
k=5
The area of the right angled triangle is 8 cm^2.
According the statement
we have to find the area of the right angled triangle with the help of the given equation.
So, For this purpose, we know that the
A right-angled triangle is a type of triangle that has one of its angles equal to 90 degrees. The other two angles sum up to 90 degrees.
From the given information:
The length of the perpendicular side (call as a) = 2cm
And
The length of the base side (call as b) = 8cm
We know that the area of the right angle triangle is :
Area = ab /2
Then
substitute the terms in it then
Area = 2*8/2
Area = 8 cm^2.
So, The area of the right angled triangle is 8 cm^2.
Learn more about right angled triangle here
brainly.com/question/64787
#SPJ1
