First we need to determine what the 6 angles must add to. Turns out we use this formula
S = 180(n-2)
where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get
S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720
The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20, 2y-20, 2y-20, <span>
They add up and must be equal to 720, so let's set up the equation to get...
(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720
Let's solve for y
</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720
10y-80 = 720
10y-80+80 = 720+80
<span>10y = 800
</span>
10y/10 = 800/10
y = 80
Now that we know the value of y, we can figure out the six angles
angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
Range: maximum - minimum
IQR: third quartile - first quartile
median: middle number once all numbers are put in numerical order
Answer:
53
Step-by-step explanation:
Sum of interior angles of a pentagon = 540°
Therefore,
2x° +2x° + 3x° + 3x° + 10 = 540°
10x° + 10° = 540°
10x° = 540° - 10°
10x° = 530°
10x = 530
x = 530/10
x = 53
I think you can solve it by
=(x^2 - y^2) *( x^2 + y^2)
= (x -y)*(x+y)*(x^2 + y^2)
Answer:
<h2>C) x = 22</h2><h2 />
Step-by-step explanation:
3x + 3x + 48 = 180
6x = 180 - 48
x = 132 / 6
x = 22
